Ifomula yokubala icompressor yomoya kunye nomgaqo!
Njengeenjineli eziqhelanisa neecompressor zomoya, ukongeza ekuqondeni ukusebenza kwemveliso yenkampani yakho, ezinye izibalo ezibandakanyekayo kweli nqaku zikwabalulekile, kungenjalo, imvelaphi yakho yobuchwephesha iya kuba luthuthu kakhulu.
(Umzobo weSchematic, ongahambelaniyo nayo nayiphi na imveliso ethile kwinqaku)
1. Ukukhutshwa kweyunithi yokuguqulwa kwe "square standard" kunye "cubic"
1Nm3/min (isikwere esiqhelekileyo) s1.07m3/min
Ke, kwenzeka njani oku kuguqulwa?Malunga nenkcazelo yesikwere esisemgangathweni kunye netyhubhiki:
pV=nRT
Phantsi kwezi zizwe zimbini, uxinzelelo, ubungakanani bemiba, kunye nezinto ezingaguquguqukiyo ziyafana, kwaye umahluko kuphela liqondo lobushushu (ubushushu be-thermodynamic K) buchongwa: Vi/Ti=V2/T2 (oko kukuthi, umthetho weGay Lussac)
Cinga: V1, Ti ziityhubhu eziqhelekileyo, V2, T2 ziityhubhu
Emva koko: V1: V2=Ti: T2
Oko kukuthi: Vi: Vz=273: 293
Ngoko: Vis1.07V2
Isiphumo: 1Nm3/mins1.07m3/min
Okwesibini, zama ukubala ukusetyenziswa kwamafutha kwi-compressor yomoya
Kwicompressor yomoya ene-250kW, 8kg, displacement ye-40m3/min, kunye nomxholo we-oyile we-3PPM, zingaphi iilitha ze-oyile eziza kusebenzisa iyunithi ukuba iqhuba iiyure ezili-1000?
impendulo:
Ukusetyenziswa kwamafutha ngecubic meter ngomzuzu:
3x 1.2=36mg/m3
, 40 cubic metres ngomzuzu ukusetyenziswa kwamafutha:
40×3.6/1000=0.144g
Ukusetyenziswa kwamafutha emva kokubaleka iiyure eziyi-1000:
-1000x60x0.144=8640g=8.64kg
Iguqulelwe kumthamo 8.64/0.8=10.8L
(Ukubaluleka kwe-oyile yokuthambisa malunga ne-0.8)
Oku ngasentla kuphela kukusetyenziswa kwe-fuel theory, ngokwenene kukhulu kunolu xabiso (i-oil separator core filter iyaqhubeka nokuhla), ukuba ibalwa ngokusekelwe kwiiyure ezingama-4000, i-compressor yomoya ye-cubic 40 iya kuqhuba ubuncinane iilitha ezingama-40 (imiphanda emibini) yeoli.Ngokuqhelekileyo, malunga ne-10-12 imibhobho (i-18 ilitha / umgqomo) ifakwe i-refueled ukwenzela ukugcinwa kwe-air compressor ye-40-square-meter, kunye nokusetyenziswa kwepetroli malunga ne-20%.
3. Ukubalwa komthamo wegesi ethafeni
Bala ukufuduswa kwecompressor yomoya ukusuka ethafeni ukuya kwithafa:
Ifomula yokucaphula:
V1/V2=R2/R1
V1=umthamo womoya kwindawo engenanto, V2=umthamo womoya kwindawo yethafa
I-R1=i-compression ratio yethafa, i-R2=i-compression ratio ye-plateau
Umzekelo: I-compressor yomoya yi-110kW, uxinzelelo lwe-exhaust yi-8bar, kunye nesantya sokuhamba kwevolumu yi-20m3 / min.Yintoni ukufuduswa kwale modeli kwindawo yokuphakama kweemitha ezingama-2000?Qhagamshelana netafile yoxinzelelo lwebarometric ehambelana nomphakamo)
Isisombululo: Ngokwefomula ethi V1/V2= R2/R1
(ileyibhile 1 icacile, 2 lithafa)
V2=ViR1/R2R1=9/1=9
R2=(8+0.85)/0.85=10.4
V2=20×9/10.4=17.3m3/min
Emva koko: umthamo wokukhupha lo mzekelo ngu-17.3m3 / min kwindawo yokuphakama kweemitha ezingama-2000, oku kuthetha ukuba ukuba le compressor yomoya isetyenziswe kwiindawo zeplateau, umthamo wokukhupha uya kuncitshiswa kakhulu.
Ke ngoko, ukuba abathengi abakwiindawo zamathafa badinga inani elithile lomoya ocinezelekileyo, kufuneka bathathele ingqalelo ukuba ukufuduswa kwecompressor yethu yomoya kunokuhlangabezana neemfuno emva kokuthotywa komgangatho ophezulu.
Ngelo xesha, abathengi abaninzi ababeka phambili iimfuno zabo, ngakumbi ezo ziyilwe liziko loyilo, bahlala bethanda ukusebenzisa iyunithi ye-Nm3 / min, kwaye kufuneka bahlawule ingqalelo ekuguquleni ngaphambi kokubala.
4. Ukubalwa kwexesha lokuzaliswa kwe-compressor yomoya
Kuthatha ixesha elingakanani ukuba icompressor yomoya igcwalise itanki?Nangona olu balo lungeloncedo kakhulu, aluchanekanga kwaye lunokuba luqikelelo kuphela.Nangona kunjalo, abasebenzisi abaninzi basazimisele ukuzama le ndlela ngaphandle kwamathandabuzo malunga nokufuduswa kwe-compressor yomoya, kusekho iimeko ezininzi zolu balo.
Eyokuqala ngumgaqo wolu balo: eneneni luguqulo lomthamo weendawo ezimbini zegesi.Okwesibini isizathu sephutha elikhulu lokubala: okokuqala, akukho mqathango wokulinganisa idatha efunekayo kwisayithi, njengokushisa, ngoko inokungahoywa kuphela;okwesibini, ukusebenza kwangempela komlinganiselo akunakuchaneka, njengokutshintshela kwisimo sokuZaliswa.
Nangona kunjalo, nangona kunjalo, ukuba kukho imfuneko, kusafuneka sazi ukuba luhlobo luni lwendlela yokubala:
Umzekelo: Kuthatha ixesha elingakanani ukuba i-10m3/min, i-8bar air compressor igcwalise itanki yokugcina igesi eyi-2m3?Lwazi : Kugcwele ntoni?Oko kukuthi, i-compressor yomoya idityaniswe ne-2 cubic metres yokugcina igesi, kunye ne-valve yokugcina igesi yokukhupha i-valve yivale de i-compressor yomoya ibethe i-8 bar ukuze ikhuphe, kunye noxinzelelo lwe-gauge yebhokisi yokugcina igesi nayo i-8 bar. .Lithatha ixesha elingakanani eli xesha?Qaphela: Eli xesha lifuna ukubalwa ukususela ekuqaleni kokulayisha i-compressor yomoya, kwaye ayikwazi ukubandakanya ukuguqulwa kweenkwenkwezi ze-delta yangaphambili okanye inkqubo yokuguqulwa kwe-frequency up-converter.Yingakho umonakalo owenziwe kwisayithi awukwazi ukuchaneka.Ukuba kukho i-bypass kumbhobho oqhagamshelwe kwi-compressor yomoya, impazamo iya kuba yincinci ukuba i-compressor yomoya ilayishwe ngokupheleleyo kwaye itshintshe ngokukhawuleza kwipayipi yokuzalisa itanki yokugcina umoya.
Okokuqala eyona ndlela ilula (uqikelelo) :
Ngaphandle kobushushu:
piVi=pzVz (Boyle-Malliot Law) Ngale fomula, kufunyaniswa ukuba utshintsho kumthamo wegesi ngokwenene luxinzelelo loxinzelelo.
Emva koko: t=Vi/ (V2/R) min
(Inombolo 1 ngumthamo wetanki yokugcina umoya, kwaye i-2 yi-volume flow of the air compressor)
t=2m3/ (10m3/9) min= 1.8min
Kuthatha malunga nemizuzu eyi-1.8 ukuhlawula ngokupheleleyo, okanye malunga nomzuzu omnye kunye nemizuzwana engama-48
ilandelwa yi-algorithm entsonkothileyo kancinane
kuxinzelelo lwegeyiji)
cacisa
Q0 -Ukuhamba kwevolumu yeCompressor m3/min ngaphandle kwe-condensate:
Vk - umthamo wetanki m3:
T – ixesha lokunyuka kwamaxabiso ezinto;
px1 – uxinzelelo lokufunxa ngecompressor MPa:
Tx1 – iqondo lobushushu lokufunxa icompressor K:
pk1 - uxinzelelo lwegesi MPa kwitanki yokugcina igesi ekuqaleni kokunyuka kwamaxabiso;
pk2 - Uxinzelelo lwegesi MPa kwitanki yokugcina igesi emva kokuphela kokunyuka kwamaxabiso kunye nobushushu obulungeleleneyo:
Tk1 – ubushushu berhasi K etankini ekuqaleni kokutshaja:
Tk2 - Ubushushu berhasi K kwitanki yokugcina igesi emva kokuphela kokutshaja kwerhasi kunye nokulingana kwe-thermal
Tk – iqondo lobushushu legesi K etankini.
5. Ukubalwa kokuSetyenziswa komoya kweZixhobo zoMoya
Indlela yokubala yokusetyenziswa komoya yenkqubo yomthombo womoya yesixhobo ngasinye somoya xa sisebenza rhoqo (ukusetyenziswa kwangoko kunye nokuyeka):
Qmax- olona setyenziso luphezulu lomoya olufunekayo
Induli - into yokusetyenziswa.Ithathela ingqalelo i-coefficient yokuba zonke izixhobo ze-pneumatic aziyi kusetyenziswa ngexesha elinye.Ixabiso leempirical yi-0.95~0.65.Ngokuqhelekileyo, inani lezixhobo ze-pneumatic lininzi, lincinci ukusetyenziswa kwangaxeshanye, kunye nexabiso elincinci, kungenjalo ixabiso elikhulu.I-0.95 yezixhobo ezi-2, i-0.9 yezixhobo ezi-4, i-0.85 yezixhobo ezi-6, i-0.8 yezixhobo ezi-8, kunye ne-0.65 kwizixhobo ezingaphezu kwe-10.
I-K1 - i-coefficient yokuvuza, ixabiso likhethwa ngaphakathi kwi-1.2 ukuya kwi-15
I-K2 - I-coefficient egciniweyo, ixabiso likhethiweyo kuluhlu lwe-1.2 ~ 1.6.
I-K3 – i-coefficient engalinganiyo
Ijonga ukuba kukho izinto ezingalinganiyo ekubaleni umyinge wokusetyenziswa kwegesi kwinkqubo yomthombo wegesi, kwaye imiselwe ukuqinisekisa ukusetyenziswa okuphezulu, kwaye ixabiso layo li-1.2.
~1.4 Ukhetho lwasekhaya lwabalandeli.
6. Xa umthamo womoya unganelanga, bala umahluko womthamo womoya
Ngenxa yokunyuka kwezixhobo zokusetyenziswa komoya, ukunikezelwa komoya akwanelanga, kwaye ingakanani i-compressors yomoya ekufuneka yongezwe ukuze kugcinwe uxinzelelo lokusebenza olulinganisiweyo lunokwaneliswa.ifomula:
Q Okwenyani - isantya sokuhamba kwecompressor yomoya efunwa yinkqubo phantsi kwemeko yokwenyani,
I-QOriginal - umyinge wokuhamba komkhweli we-compressor yomoya yokuqala;
Isivumelwano - iMPa yoxinzelelo enokuthi iphunyezwe phantsi kweemeko zokwenyani;
I-P yoqobo - uxinzelelo olusebenzayo lweMPa olunokufezekiswa ngokusetyenziswa kokuqala;
I-AQ- i-volumetric flow iya kwandiswa (m3/min)
Umzekelo: Icompressor yokuqala yomoya yi-10 cubic metres kunye ne-8 kg.Umsebenzisi ukwandisa izixhobo kunye noxinzelelo lwe-compressor yomoya yangoku inokubetha kuphela i-5 kg.Buza, ingakanani icompressor yomoya ekufuneka yongezwe ukuhlangabezana nemfuno yomoya ye-8 kg.
AQ=10* (0.8-0.5) / (0.5+0.1013)
s4.99m3/min
Ngoko ke: i-compressor yomoya ene-displacement ubuncinane ye-4.99 cubic metres kunye ne-8 kilograms iyadingeka.
Enyanisweni, umgaqo wale fomyula kukuba: ngokubala ukuhlukana koxinzelelo olujoliswe kuyo, libalela umlinganiselo woxinzelelo lwangoku.Lo mlinganiso usetyenziswe kwisantya sokuhamba kwe-compressor yomoya esetyenziswayo ngoku, oko kukuthi, ixabiso elivela kwinqanaba elijoliswe kuyo lifunyenwe.
